Distance from Thornbury to San Cesareo
The shortest distance (air line) between Thornbury and San Cesareo is 988.73 mi (1,591.20 km).
How far is Thornbury from San Cesareo
Thornbury is located in Bath and North East Somerset; North Somerset and South Gloucestershire, United Kingdom within 51° 36' 33.84" N -3° 28' 30.36" W (51.6094, -2.5249) coordinates. The local time in Thornbury is 12:50 (10.03.2025)
San Cesareo is located in Roma, Italy within 41° 49' 0.12" N 12° 48' 0" E (41.8167, 12.8000) coordinates. The local time in San Cesareo is 13:50 (10.03.2025)
The calculated flying distance from San Cesareo to San Cesareo is 988.73 miles which is equal to 1,591.20 km.
Thornbury, Bath and North East Somerset; North Somerset and South Gloucestershire, United Kingdom