Distance from Titusville to Begijnendijk
The shortest distance (air line) between Titusville and Begijnendijk is 4,528.07 mi (7,287.22 km).
How far is Titusville from Begijnendijk
Titusville is located in Florida, United States within 28° 34' 21.72" N -81° 10' 50.52" W (28.5727, -80.8193) coordinates. The local time in Titusville is 15:45 (15.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 21:45 (15.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,528.07 miles which is equal to 7,287.22 km.
Titusville, Florida, United States
Related Distances from Titusville
Begijnendijk, Arr. Leuven, Belgium