Distance from Titusville to Sint-Andries
The shortest distance (air line) between Titusville and Sint-Andries is 4,457.74 mi (7,174.04 km).
How far is Titusville from Sint-Andries
Titusville is located in Florida, United States within 28° 34' 21.72" N -81° 10' 50.52" W (28.5727, -80.8193) coordinates. The local time in Titusville is 16:40 (07.04.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 22:40 (07.04.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,457.74 miles which is equal to 7,174.04 km.
Titusville, Florida, United States
Related Distances from Titusville
Sint-Andries, Arr. Brugge, Belgium