Distance from Valkenswaard to Fayetteville
The shortest distance (air line) between Valkenswaard and Fayetteville is 4,695.13 mi (7,556.08 km).
How far is Valkenswaard from Fayetteville
Valkenswaard is located in Zuidoost-Noord-Brabant, Netherlands within 51° 21' 0" N 5° 28' 0.12" E (51.3500, 5.4667) coordinates. The local time in Valkenswaard is 18:47 (18.12.2025)
Fayetteville is located in Arkansas, United States within 36° 4' 17.04" N -95° 50' 2.04" W (36.0714, -94.1661) coordinates. The local time in Fayetteville is 11:47 (18.12.2025)
The calculated flying distance from Fayetteville to Fayetteville is 4,695.13 miles which is equal to 7,556.08 km.
Valkenswaard, Zuidoost-Noord-Brabant, Netherlands
Related Distances from Valkenswaard
Fayetteville, Arkansas, United States