Distance from Vetraz-Monthoux to Alexandroupoli
The shortest distance (air line) between Vetraz-Monthoux and Alexandroupoli is 1,045.94 mi (1,683.27 km).
How far is Vetraz-Monthoux from Alexandroupoli
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 19:12 (11.05.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 20:12 (11.05.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,045.94 miles which is equal to 1,683.27 km.
Vetraz-Monthoux, Haute-Savoie, France