Distance from Vetraz-Monthoux to Ampelokipoi
The shortest distance (air line) between Vetraz-Monthoux and Ampelokipoi is 916.90 mi (1,475.61 km).
How far is Vetraz-Monthoux from Ampelokipoi
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 15:41 (10.05.2025)
Ampelokipoi is located in Thessaloniki, Greece within 40° 38' 60" N 22° 55' 0.12" E (40.6500, 22.9167) coordinates. The local time in Ampelokipoi is 16:41 (10.05.2025)
The calculated flying distance from Ampelokipoi to Ampelokipoi is 916.90 miles which is equal to 1,475.61 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Ampelokipoi, Thessaloniki, Greece