Distance from Vetraz-Monthoux to Asenovgrad
The shortest distance (air line) between Vetraz-Monthoux and Asenovgrad is 964.56 mi (1,552.31 km).
How far is Vetraz-Monthoux from Asenovgrad
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 00:58 (23.04.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 01:58 (23.04.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 964.56 miles which is equal to 1,552.31 km.
Vetraz-Monthoux, Haute-Savoie, France