Distance from Vetraz-Monthoux to Begijnendijk
The shortest distance (air line) between Vetraz-Monthoux and Begijnendijk is 341.37 mi (549.38 km).
How far is Vetraz-Monthoux from Begijnendijk
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 21:23 (16.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 21:23 (16.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 341.37 miles which is equal to 549.38 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Begijnendijk, Arr. Leuven, Belgium