Distance from Vetraz-Monthoux to Diepenbeek
The shortest distance (air line) between Vetraz-Monthoux and Diepenbeek is 329.25 mi (529.88 km).
How far is Vetraz-Monthoux from Diepenbeek
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 06:52 (15.11.2024)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 06:52 (15.11.2024)
The calculated flying distance from Diepenbeek to Diepenbeek is 329.25 miles which is equal to 529.88 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Diepenbeek, Arr. Hasselt, Belgium