Distance from Vetraz-Monthoux to Dunakeszi
The shortest distance (air line) between Vetraz-Monthoux and Dunakeszi is 615.84 mi (991.10 km).
How far is Vetraz-Monthoux from Dunakeszi
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 06:14 (11.05.2025)
Dunakeszi is located in Pest, Hungary within 47° 37' 49.08" N 19° 8' 28.32" E (47.6303, 19.1412) coordinates. The local time in Dunakeszi is 06:14 (11.05.2025)
The calculated flying distance from Dunakeszi to Dunakeszi is 615.84 miles which is equal to 991.10 km.
Vetraz-Monthoux, Haute-Savoie, France