Distance from Vetraz-Monthoux to Kaltenkirchen
The shortest distance (air line) between Vetraz-Monthoux and Kaltenkirchen is 554.41 mi (892.23 km).
How far is Vetraz-Monthoux from Kaltenkirchen
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 01:30 (06.05.2025)
Kaltenkirchen is located in Segeberg, Germany within 53° 50' 22.92" N 9° 57' 37.08" E (53.8397, 9.9603) coordinates. The local time in Kaltenkirchen is 01:30 (06.05.2025)
The calculated flying distance from Kaltenkirchen to Kaltenkirchen is 554.41 miles which is equal to 892.23 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Kaltenkirchen, Segeberg, Germany