Distance from Vetraz-Monthoux to Mercato San Severino
The shortest distance (air line) between Vetraz-Monthoux and Mercato San Severino is 565.86 mi (910.66 km).
How far is Vetraz-Monthoux from Mercato San Severino
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 16:29 (21.05.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 16:29 (21.05.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 565.86 miles which is equal to 910.66 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Mercato San Severino, Salerno, Italy