Distance from Vetraz-Monthoux to Mladenovac
The shortest distance (air line) between Vetraz-Monthoux and Mladenovac is 711.17 mi (1,144.52 km).
How far is Vetraz-Monthoux from Mladenovac
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 23:32 (08.06.2025)
Mladenovac is located in City of Belgrade, Serbia within 44° 25' 59.88" N 20° 41' 60" E (44.4333, 20.7000) coordinates. The local time in Mladenovac is 23:32 (08.06.2025)
The calculated flying distance from Mladenovac to Mladenovac is 711.17 miles which is equal to 1,144.52 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Mladenovac, City of Belgrade, Serbia