Distance from Vetraz-Monthoux to Sainte-Savine
The shortest distance (air line) between Vetraz-Monthoux and Sainte-Savine is 179.36 mi (288.66 km).
How far is Vetraz-Monthoux from Sainte-Savine
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 13:57 (29.04.2025)
Sainte-Savine is located in Aube, France within 48° 17' 40.92" N 4° 2' 56.04" E (48.2947, 4.0489) coordinates. The local time in Sainte-Savine is 13:57 (29.04.2025)
The calculated flying distance from Sainte-Savine to Sainte-Savine is 179.36 miles which is equal to 288.66 km.
Vetraz-Monthoux, Haute-Savoie, France