Distance from Vetraz-Monthoux to Sajoszentpeter
The shortest distance (air line) between Vetraz-Monthoux and Sajoszentpeter is 692.44 mi (1,114.37 km).
How far is Vetraz-Monthoux from Sajoszentpeter
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 04:42 (12.05.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 04:42 (12.05.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 692.44 miles which is equal to 1,114.37 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary