Distance from Vetraz-Monthoux to Sansepolcro
The shortest distance (air line) between Vetraz-Monthoux and Sansepolcro is 339.53 mi (546.42 km).
How far is Vetraz-Monthoux from Sansepolcro
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 00:31 (21.05.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 00:31 (21.05.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 339.53 miles which is equal to 546.42 km.
Vetraz-Monthoux, Haute-Savoie, France