Distance from Vetraz-Monthoux to Sarospatak
The shortest distance (air line) between Vetraz-Monthoux and Sarospatak is 731.97 mi (1,178.00 km).
How far is Vetraz-Monthoux from Sarospatak
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 02:45 (12.05.2025)
Sarospatak is located in Borsod-Abaúj-Zemplén, Hungary within 48° 19' 8.4" N 21° 33' 59.04" E (48.3190, 21.5664) coordinates. The local time in Sarospatak is 02:45 (12.05.2025)
The calculated flying distance from Sarospatak to Sarospatak is 731.97 miles which is equal to 1,178.00 km.
Vetraz-Monthoux, Haute-Savoie, France
Related Distances from Vetraz-Monthoux
Sarospatak, Borsod-Abaúj-Zemplén, Hungary