Distance from Vianden to Jefferson Hills
The shortest distance (air line) between Vianden and Jefferson Hills is 4,016.55 mi (6,464.02 km).
How far is Vianden from Jefferson Hills
Vianden is located in Luxembourg, Luxembourg within 49° 56' 0.96" N 6° 12' 27" E (49.9336, 6.2075) coordinates. The local time in Vianden is 04:55 (24.02.2025)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 22:55 (23.02.2025)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 4,016.55 miles which is equal to 6,464.02 km.
Vianden, Luxembourg, Luxembourg
Related Distances from Vianden
| Cities | Distance |
|---|---|
| Vianden to Diekirch | 5.06 mi (8.14 km) |
| Vianden to Clervaux | 11.16 mi (17.96 km) |
| Vianden to Wiltz | 12.40 mi (19.96 km) |
| Vianden to Echternach | 12.72 mi (20.48 km) |
| Vianden to Mersch | 13.56 mi (21.82 km) |
| Vianden to Redange-sur-Attert | 18.34 mi (29.51 km) |
| Vianden to Grevenmacher | 20.36 mi (32.77 km) |
| Vianden to Capellen | 22.22 mi (35.76 km) |
| Vianden to Luxembourg | 22.50 mi (36.20 km) |
| Vianden to Remich | 27.81 mi (44.76 km) |
| Vianden to Dudelange | 31.60 mi (50.86 km) |
| Vianden to Differdange | 31.73 mi (51.07 km) |
| Vianden to Esch-sur-Alzette | 31.83 mi (51.23 km) |
Jefferson Hills, Pennsylvania, United States