Distance from Vineland to Sulzbach-Rosenberg
The shortest distance (air line) between Vineland and Sulzbach-Rosenberg is 4,091.61 mi (6,584.81 km).
How far is Vineland from Sulzbach-Rosenberg
Vineland is located in New Jersey, United States within 39° 27' 55.08" N -75° 0' 6.84" W (39.4653, -74.9981) coordinates. The local time in Vineland is 10:44 (14.03.2025)
Sulzbach-Rosenberg is located in Amberg-Sulzbach, Germany within 49° 30' 0" N 11° 45' 0" E (49.5000, 11.7500) coordinates. The local time in Sulzbach-Rosenberg is 16:44 (14.03.2025)
The calculated flying distance from Sulzbach-Rosenberg to Sulzbach-Rosenberg is 4,091.61 miles which is equal to 6,584.81 km.
Vineland, New Jersey, United States
Related Distances from Vineland
Sulzbach-Rosenberg, Amberg-Sulzbach, Germany