Distance from Virginia Beach to Oranienburg
The shortest distance (air line) between Virginia Beach and Oranienburg is 4,226.48 mi (6,801.86 km).
How far is Virginia Beach from Oranienburg
Virginia Beach is located in Virginia, United States within 36° 44' 0.6" N -77° 57' 23.4" W (36.7335, -76.0435) coordinates. The local time in Virginia Beach is 01:32 (12.03.2025)
Oranienburg is located in Oberhavel, Germany within 52° 45' 15.84" N 13° 14' 12.84" E (52.7544, 13.2369) coordinates. The local time in Oranienburg is 07:32 (12.03.2025)
The calculated flying distance from Oranienburg to Oranienburg is 4,226.48 miles which is equal to 6,801.86 km.
Virginia Beach, Virginia, United States
Related Distances from Virginia Beach
Oranienburg, Oberhavel, Germany