Distance from Vladimirci to Chestnut Ridge
The shortest distance (air line) between Vladimirci and Chestnut Ridge is 4,477.86 mi (7,206.42 km).
How far is Vladimirci from Chestnut Ridge
Vladimirci is located in Mačvanska oblast, Serbia within 44° 37' 0.12" N 19° 46' 59.88" E (44.6167, 19.7833) coordinates. The local time in Vladimirci is 11:33 (06.10.2025)
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 05:33 (06.10.2025)
The calculated flying distance from Chestnut Ridge to Chestnut Ridge is 4,477.86 miles which is equal to 7,206.42 km.
Vladimirci, Mačvanska oblast, Serbia
Related Distances from Vladimirci
Chestnut Ridge, New York, United States