Distance from Vladimirci to Secaucus
The shortest distance (air line) between Vladimirci and Secaucus is 4,491.24 mi (7,227.96 km).
How far is Vladimirci from Secaucus
Vladimirci is located in Mačvanska oblast, Serbia within 44° 37' 0.12" N 19° 46' 59.88" E (44.6167, 19.7833) coordinates. The local time in Vladimirci is 00:58 (17.12.2025)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 18:58 (16.12.2025)
The calculated flying distance from Secaucus to Secaucus is 4,491.24 miles which is equal to 7,227.96 km.
Vladimirci, Mačvanska oblast, Serbia
Related Distances from Vladimirci
Secaucus, New Jersey, United States