Distance from Vladimirci to Waterbury
The shortest distance (air line) between Vladimirci and Waterbury is 4,415.97 mi (7,106.82 km).
How far is Vladimirci from Waterbury
Vladimirci is located in Mačvanska oblast, Serbia within 44° 37' 0.12" N 19° 46' 59.88" E (44.6167, 19.7833) coordinates. The local time in Vladimirci is 13:29 (03.01.2026)
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 07:29 (03.01.2026)
The calculated flying distance from Waterbury to Waterbury is 4,415.97 miles which is equal to 7,106.82 km.
Vladimirci, Mačvanska oblast, Serbia
Related Distances from Vladimirci
Waterbury, Connecticut, United States