Distance from Waimalu to Sveti Ivan Zelina
The shortest distance (air line) between Waimalu and Sveti Ivan Zelina is 7,768.99 mi (12,502.97 km).
How far is Waimalu from Sveti Ivan Zelina
Waimalu is located in Hawaii, United States within 21° 23' 28.68" N -158° 3' 55.8" W (21.3913, -157.9345) coordinates. The local time in Waimalu is 20:24 (26.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 07:24 (27.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 7,768.99 miles which is equal to 12,502.97 km.
Waimalu, Hawaii, United States
Related Distances from Waimalu
Sveti Ivan Zelina, Zagrebačka županija, Croatia