Distance from Waipahu to Bad Sassendorf
The shortest distance (air line) between Waipahu and Bad Sassendorf is 7,325.93 mi (11,789.94 km).
How far is Waipahu from Bad Sassendorf
Waipahu is located in Hawaii, United States within 21° 23' 9.24" N -159° 59' 23.64" W (21.3859, -158.0101) coordinates. The local time in Waipahu is 09:28 (13.03.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 20:28 (13.03.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 7,325.93 miles which is equal to 11,789.94 km.
Waipahu, Hawaii, United States
Related Distances from Waipahu
Bad Sassendorf, Soest, Germany