Distance from Walnut to Aleksandrow Kujawski
The shortest distance (air line) between Walnut and Aleksandrow Kujawski is 5,888.91 mi (9,477.28 km).
How far is Walnut from Aleksandrow Kujawski
Walnut is located in California, United States within 34° 2' 0.24" N -118° 8' 26.52" W (34.0334, -117.8593) coordinates. The local time in Walnut is 07:09 (19.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 16:09 (19.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,888.91 miles which is equal to 9,477.28 km.
Walnut, California, United States
Related Distances from Walnut
Aleksandrow Kujawski, Włocławski, Poland