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      Distance from Walnut to San Juan de Aznalfarache

      The shortest distance (air line) between Walnut and San Juan de Aznalfarache is 5,843.24 mi (9,403.78 km).

      How far is Walnut from San Juan de Aznalfarache

      Walnut is located in California, United States within 34° 2' 0.24" N -118° 8' 26.52" W (34.0334, -117.8593) coordinates. The local time in Walnut is 12:02 (27.05.2025)

      San Juan de Aznalfarache is located in Sevilla, Spain within 37° 22' 0.12" N -7° 58' 59.88" W (37.3667, -6.0167) coordinates. The local time in San Juan de Aznalfarache is 21:02 (27.05.2025)

      The calculated flying distance from San Juan de Aznalfarache to San Juan de Aznalfarache is 5,843.24 miles which is equal to 9,403.78 km.

      Walnut, California, United States

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      San Juan de Aznalfarache, Sevilla, Spain

      Related Distances to San Juan de Aznalfarache