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      Distance from Walnut Creek to Petersberg

      The shortest distance (air line) between Walnut Creek and Petersberg is 5,659.55 mi (9,108.17 km).

      How far is Walnut Creek from Petersberg

      Walnut Creek is located in California, United States within 37° 54' 8.64" N -123° 57' 36.36" W (37.9024, -122.0399) coordinates. The local time in Walnut Creek is 22:06 (10.05.2025)

      Petersberg is located in Fulda, Germany within 50° 34' 0.12" N 9° 43' 0.12" E (50.5667, 9.7167) coordinates. The local time in Petersberg is 07:06 (11.05.2025)

      The calculated flying distance from Petersberg to Petersberg is 5,659.55 miles which is equal to 9,108.17 km.

      Walnut Creek, California, United States

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      Petersberg, Fulda, Germany

      Related Distances to Petersberg

      CitiesDistance
      Frankfurt to Petersberg55.45 mi (89.23 km)
      Wiesbaden to Petersberg73.23 mi (117.85 km)
      Mannheim to Petersberg92.94 mi (149.57 km)
      Nuremberg to Petersberg97.78 mi (157.37 km)
      Bielefeld to Petersberg112.72 mi (181.40 km)
      Bonn to Petersberg115.21 mi (185.41 km)
      Dortmund to Petersberg117.73 mi (189.47 km)
      Wuppertal to Petersberg120.48 mi (193.89 km)
      Karlsruhe to Petersberg122.51 mi (197.16 km)
      Cologne to Petersberg123.48 mi (198.73 km)
      Hannover to Petersberg124.37 mi (200.15 km)
      Bochum to Petersberg125.73 mi (202.35 km)
      Stuttgart to Petersberg125.93 mi (202.66 km)
      Leipzig to Petersberg127.43 mi (205.09 km)
      Gelsenkirchen to Petersberg131.25 mi (211.23 km)
      Munster to Petersberg132.18 mi (212.72 km)
      Essen to Petersberg132.45 mi (213.16 km)
      Dusseldorf to Petersberg135.86 mi (218.64 km)
      Duisburg to Petersberg141.75 mi (228.12 km)
      Augsburg to Petersberg160.84 mi (258.85 km)
      Bremen to Petersberg178.23 mi (286.83 km)
      Dresden to Petersberg178.78 mi (287.72 km)
      Munich to Petersberg187.51 mi (301.77 km)
      Hamburg to Petersberg206.48 mi (332.29 km)
      Berlin to Petersberg208.12 mi (334.94 km)