Distance from Walnut Park to Bad Segeberg
The shortest distance (air line) between Walnut Park and Bad Segeberg is 5,633.47 mi (9,066.19 km).
How far is Walnut Park from Bad Segeberg
Walnut Park is located in California, United States within 33° 58' 5.52" N -119° 46' 40.8" W (33.9682, -118.2220) coordinates. The local time in Walnut Park is 18:10 (08.05.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 03:10 (09.05.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 5,633.47 miles which is equal to 9,066.19 km.
Walnut Park, California, United States
Related Distances from Walnut Park
Bad Segeberg, Segeberg, Germany