Distance from Walnut Park to Cesky Tesin
The shortest distance (air line) between Walnut Park and Cesky Tesin is 6,078.02 mi (9,781.63 km).
How far is Walnut Park from Cesky Tesin
Walnut Park is located in California, United States within 33° 58' 5.52" N -119° 46' 40.8" W (33.9682, -118.2220) coordinates. The local time in Walnut Park is 17:00 (01.05.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 02:00 (02.05.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 6,078.02 miles which is equal to 9,781.63 km.
Walnut Park, California, United States
Related Distances from Walnut Park
Cesky Tesin, Moravskoslezský kraj, Czechia