Distance from Warrensville Heights to Scherpenheuvel
The shortest distance (air line) between Warrensville Heights and Scherpenheuvel is 3,945.03 mi (6,348.91 km).
How far is Warrensville Heights from Scherpenheuvel
Warrensville Heights is located in Ohio, United States within 41° 26' 10.68" N -82° 28' 40.08" W (41.4363, -81.5222) coordinates. The local time in Warrensville Heights is 10:25 (26.02.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 16:25 (26.02.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 3,945.03 miles which is equal to 6,348.91 km.
Warrensville Heights, Ohio, United States
Related Distances from Warrensville Heights
Scherpenheuvel, Arr. Leuven, Belgium