Distance from Waterbury to Cesson-Sevigne
The shortest distance (air line) between Waterbury and Cesson-Sevigne is 3,401.68 mi (5,474.48 km).
How far is Waterbury from Cesson-Sevigne
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 21:55 (13.03.2025)
Cesson-Sevigne is located in Ille-et-Vilaine, France within 48° 7' 14.88" N -2° 23' 47.04" W (48.1208, -1.6036) coordinates. The local time in Cesson-Sevigne is 03:55 (14.03.2025)
The calculated flying distance from Cesson-Sevigne to Cesson-Sevigne is 3,401.68 miles which is equal to 5,474.48 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Cesson-Sevigne, Ille-et-Vilaine, France