Distance from Waterbury to Diepenbeek
The shortest distance (air line) between Waterbury and Diepenbeek is 3,624.65 mi (5,833.30 km).
How far is Waterbury from Diepenbeek
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 13:56 (06.03.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 19:56 (06.03.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,624.65 miles which is equal to 5,833.30 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Diepenbeek, Arr. Hasselt, Belgium