Distance from Waterbury to Dimitrovgrad
The shortest distance (air line) between Waterbury and Dimitrovgrad is 4,601.85 mi (7,405.97 km).
How far is Waterbury from Dimitrovgrad
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 22:35 (09.03.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 04:35 (10.03.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 4,601.85 miles which is equal to 7,405.97 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Dimitrovgrad, Pirotska oblast, Serbia