Distance from Waterbury to Fontainebleau
The shortest distance (air line) between Waterbury and Fontainebleau is 3,578.50 mi (5,759.04 km).
How far is Waterbury from Fontainebleau
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 11:31 (13.03.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 17:31 (13.03.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 3,578.50 miles which is equal to 5,759.04 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Fontainebleau, Seine-et-Marne, France