Distance from Waterbury to Leopoldsburg
The shortest distance (air line) between Waterbury and Leopoldsburg is 3,612.65 mi (5,814.00 km).
How far is Waterbury from Leopoldsburg
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 20:34 (06.03.2025)
Leopoldsburg is located in Arr. Hasselt, Belgium within 51° 7' 0.84" N 5° 15' 20.88" E (51.1169, 5.2558) coordinates. The local time in Leopoldsburg is 02:34 (07.03.2025)
The calculated flying distance from Leopoldsburg to Leopoldsburg is 3,612.65 miles which is equal to 5,814.00 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Leopoldsburg, Arr. Hasselt, Belgium