Distance from Waterbury to Opglabbeek
The shortest distance (air line) between Waterbury and Opglabbeek is 3,627.56 mi (5,837.99 km).
How far is Waterbury from Opglabbeek
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 20:52 (08.03.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 02:52 (09.03.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 3,627.56 miles which is equal to 5,837.99 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Opglabbeek, Arr. Maaseik, Belgium