Distance from Waterbury to Saint-Amand-les-Eaux
The shortest distance (air line) between Waterbury and Saint-Amand-les-Eaux is 3,555.69 mi (5,722.33 km).
How far is Waterbury from Saint-Amand-les-Eaux
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 02:03 (16.03.2025)
Saint-Amand-les-Eaux is located in Nord, France within 50° 26' 53.16" N 3° 25' 36.84" E (50.4481, 3.4269) coordinates. The local time in Saint-Amand-les-Eaux is 08:03 (16.03.2025)
The calculated flying distance from Saint-Amand-les-Eaux to Saint-Amand-les-Eaux is 3,555.69 miles which is equal to 5,722.33 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Saint-Amand-les-Eaux, Nord, France