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      Distance from Waterbury to Saint-Andre-de-Cubzac

      The shortest distance (air line) between Waterbury and Saint-Andre-de-Cubzac is 3,533.71 mi (5,686.96 km).

      How far is Waterbury from Saint-Andre-de-Cubzac

      Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 02:02 (16.03.2025)

      Saint-Andre-de-Cubzac is located in Gironde, France within 44° 59' 40.92" N -1° 33' 15.12" W (44.9947, -0.4458) coordinates. The local time in Saint-Andre-de-Cubzac is 08:02 (16.03.2025)

      The calculated flying distance from Saint-Andre-de-Cubzac to Saint-Andre-de-Cubzac is 3,533.71 miles which is equal to 5,686.96 km.

      Waterbury, Connecticut, United States

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      Saint-Andre-de-Cubzac, Gironde, France

      Related Distances to Saint-Andre-de-Cubzac