Distance from Waterbury to Saint-Paul-les-Dax
The shortest distance (air line) between Waterbury and Saint-Paul-les-Dax is 3,541.74 mi (5,699.88 km).
How far is Waterbury from Saint-Paul-les-Dax
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 06:04 (16.03.2025)
Saint-Paul-les-Dax is located in Landes, France within 43° 43' 32.16" N -2° 56' 49.92" W (43.7256, -1.0528) coordinates. The local time in Saint-Paul-les-Dax is 12:04 (16.03.2025)
The calculated flying distance from Saint-Paul-les-Dax to Saint-Paul-les-Dax is 3,541.74 miles which is equal to 5,699.88 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Saint-Paul-les-Dax, Landes, France