Distance from Waterbury to Septemes-les-Vallons
The shortest distance (air line) between Waterbury and Septemes-les-Vallons is 3,840.98 mi (6,181.46 km).
How far is Waterbury from Septemes-les-Vallons
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 12:54 (16.03.2025)
Septemes-les-Vallons is located in Bouches-du-Rhône, France within 43° 23' 53.88" N 5° 21' 56.88" E (43.3983, 5.3658) coordinates. The local time in Septemes-les-Vallons is 18:54 (16.03.2025)
The calculated flying distance from Septemes-les-Vallons to Septemes-les-Vallons is 3,840.98 miles which is equal to 6,181.46 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Septemes-les-Vallons, Bouches-du-Rhône, France