Distance from Waterbury to Sint-Amandsberg
The shortest distance (air line) between Waterbury and Sint-Amandsberg is 3,553.52 mi (5,718.83 km).
How far is Waterbury from Sint-Amandsberg
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 09:03 (09.03.2025)
Sint-Amandsberg is located in Arr. Gent, Belgium within 51° 3' 14.04" N 3° 44' 57.12" E (51.0539, 3.7492) coordinates. The local time in Sint-Amandsberg is 15:03 (09.03.2025)
The calculated flying distance from Sint-Amandsberg to Sint-Amandsberg is 3,553.52 miles which is equal to 5,718.83 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Sint-Amandsberg, Arr. Gent, Belgium