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      Distance from Waterbury to Sint-Joost-ten-Node

      The shortest distance (air line) between Waterbury and Sint-Joost-ten-Node is 3,584.36 mi (5,768.47 km).

      How far is Waterbury from Sint-Joost-ten-Node

      Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 08:53 (09.03.2025)

      Sint-Joost-ten-Node is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 51' 0" N 4° 22' 59.88" E (50.8500, 4.3833) coordinates. The local time in Sint-Joost-ten-Node is 14:53 (09.03.2025)

      The calculated flying distance from Sint-Joost-ten-Node to Sint-Joost-ten-Node is 3,584.36 miles which is equal to 5,768.47 km.

      Waterbury, Connecticut, United States

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      Sint-Joost-ten-Node, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium

      Related Distances to Sint-Joost-ten-Node