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      Distance from Waterbury to Sint-Katelijne-Waver

      The shortest distance (air line) between Waterbury and Sint-Katelijne-Waver is 3,584.87 mi (5,769.28 km).

      How far is Waterbury from Sint-Katelijne-Waver

      Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 09:13 (09.03.2025)

      Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 15:13 (09.03.2025)

      The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 3,584.87 miles which is equal to 5,769.28 km.

      Waterbury, Connecticut, United States

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      Sint-Katelijne-Waver, Arr. Mechelen, Belgium

      Related Distances to Sint-Katelijne-Waver