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      Distance from Waterbury to Sint-Martens-Lennik

      The shortest distance (air line) between Waterbury and Sint-Martens-Lennik is 3,576.19 mi (5,755.32 km).

      How far is Waterbury from Sint-Martens-Lennik

      Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 08:42 (09.03.2025)

      Sint-Martens-Lennik is located in Arr. Halle-Vilvoorde, Belgium within 50° 47' 60" N 4° 9' 0" E (50.8000, 4.1500) coordinates. The local time in Sint-Martens-Lennik is 14:42 (09.03.2025)

      The calculated flying distance from Sint-Martens-Lennik to Sint-Martens-Lennik is 3,576.19 miles which is equal to 5,755.32 km.

      Waterbury, Connecticut, United States

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      Sint-Martens-Lennik, Arr. Halle-Vilvoorde, Belgium

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