Distance from Waterbury to Sint-Pieters-Leeuw
The shortest distance (air line) between Waterbury and Sint-Pieters-Leeuw is 3,580.67 mi (5,762.53 km).
How far is Waterbury from Sint-Pieters-Leeuw
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 09:10 (09.03.2025)
Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 15:10 (09.03.2025)
The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 3,580.67 miles which is equal to 5,762.53 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium