Distance from Waterbury to Six-Fours-les-Plages
The shortest distance (air line) between Waterbury and Six-Fours-les-Plages is 3,870.74 mi (6,229.36 km).
How far is Waterbury from Six-Fours-les-Plages
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 12:54 (16.03.2025)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 18:54 (16.03.2025)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 3,870.74 miles which is equal to 6,229.36 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Six-Fours-les-Plages, Var, France