Distance from Waterbury to Vetraz-Monthoux
The shortest distance (air line) between Waterbury and Vetraz-Monthoux is 3,793.83 mi (6,105.58 km).
How far is Waterbury from Vetraz-Monthoux
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 16:34 (16.03.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 22:34 (16.03.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 3,793.83 miles which is equal to 6,105.58 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Vetraz-Monthoux, Haute-Savoie, France