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      Distance from Waterbury to Villeneuve-les-Maguelone

      The shortest distance (air line) between Waterbury and Villeneuve-les-Maguelone is 3,769.50 mi (6,066.43 km).

      How far is Waterbury from Villeneuve-les-Maguelone

      Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 12:05 (17.03.2025)

      Villeneuve-les-Maguelone is located in Hérault, France within 43° 31' 55.92" N 3° 51' 38.88" E (43.5322, 3.8608) coordinates. The local time in Villeneuve-les-Maguelone is 18:05 (17.03.2025)

      The calculated flying distance from Villeneuve-les-Maguelone to Villeneuve-les-Maguelone is 3,769.50 miles which is equal to 6,066.43 km.

      Waterbury, Connecticut, United States

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      Villeneuve-les-Maguelone, Hérault, France

      Related Distances to Villeneuve-les-Maguelone