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      Distance from Waterbury to Voisins-le-Bretonneux

      The shortest distance (air line) between Waterbury and Voisins-le-Bretonneux is 3,541.81 mi (5,699.99 km).

      How far is Waterbury from Voisins-le-Bretonneux

      Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 11:07 (17.03.2025)

      Voisins-le-Bretonneux is located in Yvelines, France within 48° 45' 29.88" N 2° 3' 2.88" E (48.7583, 2.0508) coordinates. The local time in Voisins-le-Bretonneux is 17:07 (17.03.2025)

      The calculated flying distance from Voisins-le-Bretonneux to Voisins-le-Bretonneux is 3,541.81 miles which is equal to 5,699.99 km.

      Waterbury, Connecticut, United States

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      Voisins-le-Bretonneux, Yvelines, France

      Related Distances to Voisins-le-Bretonneux